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0.0625x^2+2x-10=0
a = 0.0625; b = 2; c = -10;
Δ = b2-4ac
Δ = 22-4·0.0625·(-10)
Δ = 6.5
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2)-\sqrt{6.5}}{2*0.0625}=\frac{-2-\sqrt{6.5}}{0.125} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2)+\sqrt{6.5}}{2*0.0625}=\frac{-2+\sqrt{6.5}}{0.125} $
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